Question

The dipole moment of HBr is $1.6 \times 10^{-30} $C-m and interatomic spacing is $1 \mathring{A}$. The per cent ionic character of HBr is

• A. 7
• B. 10
• C. 15
• D. 27

Answer 1

Answer: (B)

Charge of electron $= 1.6 \times 10^{-19}C$
Dipole moment of HBr $= 1.6 \times 1.6\times ^{-30}$
Inter-atomic spacing $= 1 \mathring{A}$
$\, \, \, \, \, \, \, \, \, \, \, \, \, \, \, = 1 \times 10^{-10} m$
% ionic character in HBr
$\, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, =\frac{dipole\, moment\, of\, HBr\, \times100}{inter\, spacing\, distance\, \times\, q}$
$\, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, =\frac{1.6 \times10^{-30}}{1.6 \times 10^{-19} \times\, 10^{-10}}\times100$
$\, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, =10^{-30}\times10^{29} \times100$
$\, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, =0.1\times 100$
$\, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, =10\%$