Question

The diode shown in the circuit is a silicon diode. The potential difference between the points $A$ and $B$ will be

• A. $6V$
• B. $0.6V$
• C. $0.7V$
• D. $0V$

Answer 1

Answer: (A)

Diode is in reverse bias, current $=0$,
potential difference across $R=0;V_{AB}=6V$