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  4. The diode shown in the circuit is a silicon diode. The potential difference between the points A and B will be

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Q. The diode shown in the circuit is a silicon diode. The potential difference between the points $A$ and $B$ will bePhysics Question Image

Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

Diode is in reverse bias, current $=0$,
potential difference across $R=0 ; V_{A B}=6 V$