Question

The dimensions of ${\left({\mu }_0{\epsilon }_0\right)}^{-1/2}$ are

• A. $[L^{-1}T]$
• B. $[L{T}^{-1}]$
• C. $[L^{1/2}{T}^{1/2}]$
• D. $[L^{1/2}{T}^{-1/2}]$

Answer 1

Answer: (B)

The speed of the light in vacuum is
$c=\frac{1}{\sqrt{{\mu }_0{\epsilon }_0}}={\left({\mu }_0{\epsilon }_0\right)}^{-1/2}$
$\therefore \left[{\left({\mu }_0{\epsilon }_0\right)}^{-1/2}\right]=[c]=\left[{\text{ LT }}^{-1}\right]$