Question

The dimensions of kinetic energy is:

• A. $[M^2{L}^2{T}^1]$
• B. $[M^1{L}^2{T}^1]$
• C. $[M^1{L}^2{T}^{-2}]$
• D. $[M^1{L}^2{T}^{-1}]$
• E. $[M^2{L}^2{T}^{-2}]$

Answer 1

Answer: (C)

$KE=\frac{1}{2}m{v}^2$
$\therefore$ $[KE]=[M]{[L{T}^{-1}]}^2[M{L}^2{T}^{-2}]$