Question

The dimensions of $K$ in the equation $W=\frac{1}{2}K{x}^2$ is:-

• A. $M^1{L}^0{T}^{-2}$
• B. $M^0{L}^1{T}^{-1}$
• C. $M^1{L}^1{T}^{-2}$
• D. $M^1{L}^0{T}^{-1}$

Answer 1

Answer: (A)

$W=\frac{1}{2}k{x}^2\Rightarrow [k]=\frac{[W]}{\left[x^2\right]}=\left[\frac{M{L}^2{T}^{-2}}{L^2}\right]=\left[{\text{MT}}^{-2}\right]$