The dimensions of σb4 (σ = Stefan’s constant and b = Wein’s constant) are

Question

The dimensions of σb4 (σ = Stefan’s constant and b = Wein’s constant) are (A) [M0L0T0] (B) [ML4T-3] (C) [ML-2T] (D) [ML6T-3]

Tardigrade Admin · Accepted Answer

Weinâs displacement law Î»mT = b or b4 = Î»m 4 T4 ...(i) From Stefanâs law, σ = (E/AtT4) ...(ii) From (i) and (ii), σ b4 = (EÎ»m 4 T4/AtT4) [σ b4 ] = ([ML2T-2][L]4/[L2][T]) = [ML4T-3]

Q. The dimensions of $σ b^{4}$ ( $σ =$ Stefan’s constant and b = Wein’s constant) are

$[M^{0} L^{0} T^{0}]$

$[M L^{4} T^{- 3}]$

$[M L^{- 2} T]$

$[M L^{6} T^{- 3}]$

Q. The dimensions of σb4 (σ= Stefan’s constant and b = Wein’s constant) are

[M0L0T0]

[ML4T−3]

[ML−2T]

[ML6T−3]

Wein’s displacement law λm​T=b or b4=λm4​T4...(i) From Stefan’s law, σ=AtT4E​...(ii) From (i) and (ii), σb4=AtT4Eλm4​T4​ [σb4]=[L2][T][ML2T−2][L]4​ =[ML4T−3]

Q. The dimensions of $σ b^{4}$ ( $σ =$ Stefan’s constant and b = Wein’s constant) are

$[M^{0} L^{0} T^{0}]$

$[M L^{4} T^{- 3}]$

$[M L^{- 2} T]$

$[M L^{6} T^{- 3}]$