The dimensional formula for Reynold’s number is

Question

The dimensional formula for Reynold’s number is (A) [L0 M0 T0] (B) [L1 M1 T1] (C) [L-1 M1 T1] (D) [L1 M1 T-1]

Tardigrade Admin · Accepted Answer

Reynold's number describes the ratio of inertial force per unit area to viscous force per unit areq for a flowing fluid.
Thus, Reynold's number is the ratio of two physical quantity of same dimension which cancel out each other. Hence, Reynold's number is dimensionless quantity.

Q. The dimensional formula for Reynold’s number is

$[L^{0} M^{0} T^{0}]$

$[L^{1} M^{1} T^{1}]$

$[L^{- 1} M^{1} T^{1}]$

$[L^{1} M^{1} T^{- 1}]$

Reynold's number describes the ratio of inertial force per unit area to viscous force per unit areq for a flowing fluid.
Thus, Reynold's number is the ratio of two physical quantity of same dimension which cancel out each other. Hence, Reynold's number is dimensionless quantity.

Q. The dimensional formula for Reynold’s number is

[L0M0T0]

[L1M1T1]

[L−1M1T1]

[L1M1T−1]

Reynold's number describes the ratio of inertial force per unit area to viscous force per unit areq for a flowing fluid. Thus, Reynold's number is the ratio of two physical quantity of same dimension which cancel out each other. Hence, Reynold's number is dimensionless quantity.

$[L^{0} M^{0} T^{0}]$

$[L^{1} M^{1} T^{1}]$

$[L^{- 1} M^{1} T^{1}]$

$[L^{1} M^{1} T^{- 1}]$

Reynold's number describes the ratio of inertial force per unit area to viscous force per unit areq for a flowing fluid.
Thus, Reynold's number is the ratio of two physical quantity of same dimension which cancel out each other. Hence, Reynold's number is dimensionless quantity.