The dimension of magnetic flux is

Question

The dimension of magnetic flux is (A)  [MLT-1A-1] (B)  [ML-1TA-2] (C)  [ML-2T2A-2] (D)  [ML2T-2A-1]

Tardigrade Admin · Accepted Answer

Magnetic flux (φ)=( Magnetic field) ) ×( Area ) or [φ]=[B][A] =([ text Force ][ text Area ]/[ text Current ][ text Length ])=([M L T-2][L2]/[A][L]) |φ|=[M L2 T-2 A-1]

Q. The dimension of magnetic flux is

$[M L T^{- 1} A^{- 1}]$

$[M L^{- 1} T A^{- 2}]$

$[M L^{- 2} T^{2} A^{- 2}]$

$[M L^{2} T^{- 2} A^{- 1}]$

Magnetic flux $(ϕ) = ($ Magnetic field) $) \times ($ Area $)$ or $[ϕ] = [B] [A]$
$= \frac{[ Force ] [ Area ]}{[ Current ] [ Length ]} = \frac{[ M L T ^{- 2} ] [ L ^{2} ]}{[ A ] [ L ]}$
$∣ ϕ ∣ = [M L^{2} T^{- 2} A^{- 1}]$

Q. The dimension of magnetic flux is

[MLT−1A−1]

[ML−1TA−2]

[ML−2T2A−2]

[ML2T−2A−1]

Magnetic flux (ϕ)=( Magnetic field) )×( Area ) or [ϕ]=[B][A] =[ Current ][ Length ][ Force ][ Area ]​=[A][L][MLT−2][L2]​ ∣ϕ∣=[ML2T−2A−1]

$[M L T^{- 1} A^{- 1}]$

$[M L^{- 1} T A^{- 2}]$

$[M L^{- 2} T^{2} A^{- 2}]$

$[M L^{2} T^{- 2} A^{- 1}]$

Magnetic flux $(ϕ) = ($ Magnetic field) $) \times ($ Area $)$ or $[ϕ] = [B] [A]$
$= \frac{[ Force ] [ Area ]}{[ Current ] [ Length ]} = \frac{[ M L T ^{- 2} ] [ L ^{2} ]}{[ A ] [ L ]}$
$∣ ϕ ∣ = [M L^{2} T^{- 2} A^{- 1}]$