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Tardigrade
Question
Physics
The dimension of impulse is [M2 b L3 a T4 c] . Find the value of 3a+2b-4c
Q. The dimension of impulse is
[
M
2
b
L
3
a
T
4
c
]
. Find the value of
3
a
+
2
b
−
4
c
207
169
NTA Abhyas
NTA Abhyas 2022
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Answer:
3
Solution:
Impulse,
J
=
F
×
t
∴
[
J
]
=
[
M
1
L
1
T
−
2
]
×
[
T
1
]
=
[
M
1
L
1
T
−
1
]
i
⋅
e
⋅
,
[
M
2
b
L
3
a
T
4
c
]
=
[
M
1
L
1
T
−
1
]
∴
2
b
=
1
,
3
a
=
1
,
4
c
=
−
1
2
b
+
3
a
−
4
c
=
1
+
1
−
(
−
1
)
=
1
+
1
+
1
=
3