The digit in the unit place of the number 2009 !+37886 is

Question

The digit in the unit place of the number 2009 !+37886 is (A) 9 (B) 7 (C) 3 (D) 1

Tardigrade Admin · Accepted Answer

The digit in the unit place of (2009) ! is 0 . Now, 31=3,32=9, 33=27, 34=81, 35=243 ∴ 37886=(34)1971 32 The digit in the unit place of 37886 is 9 . ∴ The digit in the unit place of (2009) !+37886 is 9 .

Q. The digit in the unit place of the number $2009! + 3^{7886}$ is

9

7

3

1

The digit in the unit place of $(2009)!$ is $0.$
Now, $3^{1} = 3, 3^{2} = 9, 3^{3} = 27, 3^{4} = 81$ ,
$3^{5} = 243$
$∴ 3^{7886} = (3^{4})^{1971} 3^{2}$
The digit in the unit place of $3^{7886}$ is $9$ .
$∴$ The digit in the unit place of $(2009)! + 3^{7886}$ is $9.$

Q. The digit in the unit place of the number 2009!+37886 is

9

7

3

1

The digit in the unit place of (2009)! is 0. Now, 31=3,32=9,33=27,34=81, 35=243 ∴37886=(34)197132 The digit in the unit place of 37886 is 9 . ∴ The digit in the unit place of (2009)!+37886 is 9.

Q. The digit in the unit place of the number $2009! + 3^{7886}$ is

The digit in the unit place of $(2009)!$ is $0.$
Now, $3^{1} = 3, 3^{2} = 9, 3^{3} = 27, 3^{4} = 81$ ,
$3^{5} = 243$
$∴ 3^{7886} = (3^{4})^{1971} 3^{2}$
The digit in the unit place of $3^{7886}$ is $9$ .
$∴$ The digit in the unit place of $(2009)! + 3^{7886}$ is $9.$