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Mathematics
The differential equation of the family of parabolas y2 = 4ax, where a is parameter, is
Q. The differential equation of the family of parabolas
y
2
=
4
a
x
, where
a
is parameter, is
5590
208
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Differential Equations
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A
d
x
d
y
=
2
x
y
35%
B
d
x
d
y
=
−
2
x
y
18%
C
d
x
d
y
=
−
y
2
x
26%
D
d
x
d
y
=
y
2
x
21%
Solution:
Given equation of parabola is
y
2
=
4
a
x
... (i)
Differentiating (i) w.r.t.
x
, we get
2
y
d
x
d
y
=
4
a
⇒
d
x
d
y
=
y
2
a
⇒
a
=
2
y
d
x
d
y
Substituting the value of a in (i), we get
y
2
=
4.
2
y
d
x
d
y
x
⇒
y
2
=
2
x
y
d
x
d
y
⇒
d
x
d
y
=
2
x
y