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Question
Mathematics
The differential equation of family of circles whose centre lies on x -axis, is
Q. The differential equation of family of circles whose centre lies on
x
-axis, is
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MHT CET 2010
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A
d
x
2
d
2
y
+
(
d
x
d
y
)
2
+
1
=
0
B
y
d
x
2
d
2
y
+
(
d
x
d
y
)
2
−
1
=
0
C
y
d
x
2
d
2
y
−
(
d
x
d
y
)
2
−
1
=
0
D
y
d
x
2
d
2
y
+
(
d
x
d
y
)
2
+
1
=
0
Solution:
The equation of family of circle having centre at
x
-axis is
x
2
+
y
2
−
2
a
x
=
0
On differentiating, we get
2
x
+
2
y
d
x
d
y
−
2
a
=
0
Again, differentiating, we get
2
+
2
[
y
d
x
2
d
2
y
+
(
d
x
d
y
)
2
]
=
0
⇒
y
d
x
2
d
2
y
+
(
d
x
d
y
)
2
+
1
=
0