The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two. The metal ion is :

Question

The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two. The metal ion is : (A) Fe2+ (B) Co2+ (C) Mn2+ (D) Ni2+

Tardigrade Admin · Accepted Answer

The difference in the number of unpaired electrons of Metal ion in its high-spin and low-spin octahedral complexes is

2.

For the metal

C o^{2 +} ([A r] 3 d^{7})

ion, the difference of unpaired electrons is

3 - 1 = 2

since the number of unpaired electrons of a metal ion in its high-spin complex is

3

and low-spin complex is

1.

Q. The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two. The metal ion is :

$F e^{2 +}$

$C o^{2 +}$

$M n^{2 +}$

$N i^{2 +}$