Question

The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two. The metal ion is :

• A. $Fe^{2+}$
• B. $Co^{2+}$
• C. $Mn^{2+}$
• D. $Ni^{2+}$

Answer 1

Answer: (B)

The difference in the number of unpaired electrons of Metal ion in its high-spin and low-spin octahedral complexes is $2 .$
For the metal $Co ^{2+}\left([ Ar ] 3 d ^{7}\right)$ ion, the difference of unpaired electrons is $3-1=2$ since the number of unpaired electrons of a metal ion in its high-spin complex is $3$ and low-spin complex is $1 .$