The difference between the maximum and minimum values of resistance of a resistor with the color scheme green-green-red-silver is

Question

The difference between the maximum and minimum values of resistance of a resistor with the color scheme green-green-red-silver is (A)  55 Ω  (B)  1100 Ω  (C)  44 Ω  (D)  440 Ω

Tardigrade Admin · Accepted Answer

Color scheme:Green - green - red - silver ∴ R=(5.5 × 103 ± 10 %) Ω=(5500 ± 10 %) Ω Rmin=(5500-550) Ω =4950 Ω Rmax=(5500+550) Ω =6050 Ω ∴ Rmax-Rmin=6050-4950 =1100 Ω

Q. The difference between the maximum and minimum values of resistance of a resistor with the color scheme green-green-red-silver is

$55 Ω$

$1100 Ω$

$44 Ω$

$440 Ω$

Color scheme:Green - green - red - silver
$∴ R = (5.5 \times 1 0^{3} \pm 10%)$
$Ω = (5500 \pm 10%) Ω$
$R_{min} = (5500 - 550)$
$Ω = 4950 Ω$
$R_{ma x} = (5500 + 550) Ω$
$= 6050 Ω$
$∴ R_{ma x} - R_{min} = 6050 - 4950$
$= 1100 Ω$

Q. The difference between the maximum and minimum values of resistance of a resistor with the color scheme green-green-red-silver is

55Ω

1100Ω

44Ω

440Ω

Color scheme:Green - green - red - silver ∴R=(5.5×103±10%) Ω=(5500±10%)Ω Rmin​=(5500−550) Ω=4950Ω Rmax​=(5500+550)Ω =6050Ω ∴Rmax​−Rmin​=6050−4950 =1100Ω

$55 Ω$

$1100 Ω$

$44 Ω$

$440 Ω$

Color scheme:Green - green - red - silver
$∴ R = (5.5 \times 1 0^{3} \pm 10%)$
$Ω = (5500 \pm 10%) Ω$
$R_{min} = (5500 - 550)$
$Ω = 4950 Ω$
$R_{ma x} = (5500 + 550) Ω$
$= 6050 Ω$
$∴ R_{ma x} - R_{min} = 6050 - 4950$
$= 1100 Ω$