The dielectric strength of a medium is 2 kVmm-1 . What is the maximum potential difference that can be set up across a 50 pm specimen without puncturing it.

Question

The dielectric strength of a medium is 2 kVmm-1 . What is the maximum potential difference that can be set up across a 50 pm specimen without puncturing it. (A) 10 V (B) 100 V (C) 1000 V (D) 10000 V

Tardigrade Admin · Accepted Answer

Dielectric strength = Potential difference gradient. Hence maximum potential difference = Dielectric strength × distance = (2000 V/mm) × 50 μ m = (2000 V/10-3 m) × 50 × 10-6 m = 100 V.

Q. The dielectric strength of a medium is $2 kVm m^{- 1}$ . What is the maximum potential difference that can be set up across a $50 p m$ specimen without puncturing it.

10 V

100 V

1000 V

10000 V

Dielectric strength = Potential difference gradient.
Hence maximum potential difference = Dielectric strength $\times$ distance
= $\frac{2000 V}{mm} \times 50 μ m = \frac{2000 V}{1 0 ^{- 3} m} \times 50 \times 1 0^{- 6} m$ = 100 V.

Q. The dielectric strength of a medium is 2kVmm−1 . What is the maximum potential difference that can be set up across a 50pm specimen without puncturing it.