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Tardigrade
Question
Chemistry
The diamagnetic species is
Q. The diamagnetic species is
2625
211
AIIMS
AIIMS 2005
Coordination Compounds
Report Error
A
[
N
i
(
CN
)
4
]
2
−
55%
B
[
N
i
C
l
4
]
2
−
16%
C
[
C
o
C
l
4
]
2
−
16%
D
[
C
o
F
6
]
3
−
13%
Solution:
Strong field ligand cause pairing of electrons
CO
>
C
N
−
>
N
O
2
−
>
N
H
3
>
Weak field ligand does not cause pairing
H
2
O
>
F
−
>
C
l
−
>
B
r
−
>
I
−
n
=
0
(diamagnetic)
d
s
p
2
hybridisation, low spin complex.
N
i
2
+
in presence of weak ligand
C
l
−
n
=
2
, paramagnetic
s
p
3
, hybridisation, high spin complex.
C
o
2
+
in presence of weak ligand
C
l
−
n
=
3
, paramagnetic,
s
p
3
hybridisation
C
o
2
+
in presence of weak ligand
F
−
n
=
5
, paramagnetic,
s
p
3
d
2
hybridisat