Write Δ=lΔ1+l′Δ2, where Δ1=∣∣abcam+a′m′bm+b′m′cm+c′m′an+a′n′bn+b′n′cn+c′n′∣∣ and Δ2=∣∣a′b′c′am+a′m′bm+b′m′cm+c′m′an+a′n′bn+b′n′cn+c′n′∣∣
In Δ1 apply C2→C2−mC1,C3→C3−nC1 to obtain Δ1=∣∣abca′m′b′m′c′m′a′n′b′n′c′n′∣∣=0
Similarly Δ2=0. Thus, Δ=0