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Tardigrade
Question
Mathematics
The determinant | cos (α +β ) - sin (α +β ) cos 2β sin α cos α sin β - cos α sin α cos β | is independent of
Q. The determinant
∣
∣
cos
(
α
+
β
)
sin
α
−
cos
α
−
sin
(
α
+
β
)
cos
α
sin
α
cos
2
β
sin
β
cos
β
∣
∣
is independent of
1670
213
Bihar CECE
Bihar CECE 2010
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A
α
B
β
C
α
and
β
D
Neither
α
nor
β
Solution:
We have the determinant
∣
∣
cos
(
α
+
β
)
sin
α
−
cos
α
−
sin
(
α
+
β
)
cos
α
sin
α
cos
2
β
sin
β
cos
β
∣
∣
R
1
→
R
1
+
(
s
in
β
)
R
2
+
(
cos
β
)
R
3
,
∣
∣
0
sin
α
−
cos
α
0
cos
α
sin
α
1
+
cos
2
β
sin
β
cos
β
∣
∣
=
(
1
+
cos
2
β
)
(
sin
2
α
+
cos
2
α
)
=
1
+
cos
2
β
which is independent of
α
.