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Tardigrade
Question
Mathematics
The derivative of ( cot x) sin x+( tan x) cos x with respect to x is
Q. The derivative of
(
cot
x
)
s
i
n
x
+
(
tan
x
)
c
o
s
x
with respect to
x
is
1912
237
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A
(
cot
x
)
s
i
n
x
[
sec
x
+
cos
x
lo
g
(
cot
x
)]
+
(
tan
x
)
c
o
s
x
[
cosec
x
−
sin
x
lo
g
(
tan
x
)]
B
(
cot
x
)
s
i
n
x
[
−
sec
x
+
cos
x
lo
g
(
cot
x
)]
+
(
tan
x
)
c
o
s
x
[
cos
ec
x
+
sin
x
lo
g
(
tan
x
)]
C
(
cot
x
)
s
i
n
x
[
sec
x
−
cos
x
lo
g
(
cot
x
)]
+
(
tan
x
)
c
o
s
x
[
cosec
x
−
sin
x
lo
g
(
tan
x
)]
D
(
cot
x
)
s
i
n
x
[
−
sec
x
+
cos
x
lo
g
(
cot
x
)]
+
(
tan
x
)
c
o
s
x
[
cos
ec
x
−
sin
x
lo
g
(
tan
x
)]
Solution:
d
x
d
[
f
(
x
)
g
(
x
)
]
=
f
(
x
)
g
(
x
)
[
g
(
x
)
f
(
x
)
f
′
(
x
)
+
g
′
(
x
)
lo
g
(
f
(
x
))
]