The density of water at 4° C is 1.0 × 103 kg m -3 The volume occupied by one molecule of water is approximately

Question

The density of water at 4° C is 1.0 × 103 kg m -3 The volume occupied by one molecule of water is approximately (A) 3.0 × 10-23 mL (B) 6.0 × 10-22 mL (C) 3.0 × 10-21 mL (D) 9.0 × 10-23 mL

Tardigrade Admin · Accepted Answer

Mass of one molecule of water =(18/6.023 × 1023) ≈ 3.0 × 10-23 Volume =3.0 × 10-23 mL (density .=103 kg m -3=1 g / mL )

Q. The density of water at $4^{\circ} C$ is $1.0 \times 1 0^{3} k g m^{- 3}$ The volume occupied by one molecule of water is approximately

$3.0 \times 1 0^{- 23} m L$

$6.0 \times 1 0^{- 22} m L$

$3.0 \times 1 0^{- 21} m L$

$9.0 \times 1 0^{- 23} m L$

Mass of one molecule of water

$= \frac{18}{6.023 \times 1 0 ^{23}} \approx 3.0 \times 1 0^{- 23}$

Volume $= 3.0 \times 1 0^{- 23} m L$ (density $= 1 0^{3} k g m^{- 3} = 1 g / m L)$

Q. The density of water at 4∘C is 1.0×103kgm−3 The volume occupied by one molecule of water is approximately

3.0×10−23mL

6.0×10−22mL

3.0×10−21mL

9.0×10−23mL