Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The density of water at 4° C is 1.0 × 103 kg m -3 The volume occupied by one molecule of water is approximately
Question Error Report
Question is incomplete/wrong
Question not belongs to this Chapter
Answer is wrong
Solution is wrong
Answer & Solution is not matching
Spelling mistake
Image missing
Website not working properly
Other (not listed above)
Error description
Thank you for reporting, we will resolve it shortly
Back to Question
Thank you for reporting, we will resolve it shortly
Q. The density of water at $4^{\circ} C$ is $1.0 \times 10^{3} kg\, m ^{-3}$ The volume occupied by one molecule of water is approximately
Some Basic Concepts of Chemistry
A
$3.0 \times 10^{-23} mL$
26%
B
$6.0 \times 10^{-22} mL$
40%
C
$3.0 \times 10^{-21} mL$
24%
D
$9.0 \times 10^{-23} mL$
10%
Solution:
Mass of one molecule of water
$=\frac{18}{6.023 \times 10^{23}} \approx 3.0 \times 10^{-23} $
Volume $=3.0 \times 10^{-23} \,mL$ (density $\left.=10^{3} \,kg \,m ^{-3}=1 g / mL \right)$