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Q. The density of water at $4^{\circ} C$ is $1.0 \times 10^{3} kg\, m ^{-3}$ The volume occupied by one molecule of water is approximately

Some Basic Concepts of Chemistry

Solution:

Mass of one molecule of water

$=\frac{18}{6.023 \times 10^{23}} \approx 3.0 \times 10^{-23} $

Volume $=3.0 \times 10^{-23} \,mL$ (density $\left.=10^{3} \,kg \,m ^{-3}=1 g / mL \right)$