The density of O2 is 16 at NTP. At what temperature(in oC) its density will be 14? Consider that the pressure remains constant.

Question

The density of O2 is 16 at NTP. At what temperature(in oC) its density will be 14? Consider that the pressure remains constant. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

As textd=( textP textM/ textR textT) textd1 textT1= textd2 textT2 When textp remains constant textd1=16; textd2=14; textT1=273 textK, textT2=? textd1 textT1= textd2 textT2 16× 273=14× textT2 textT2=312 textK textT2=312-273=39 textâ

Q. The density of $O_{2}$ is 16 at NTP. At what temperature(in ^oC) its density will be 14? Consider that the pressure remains constant.

As $d = \frac{P M}{R T}$

$d_{1} T_{1} = d_{2} T_{2}$

When $p$ remains constant

$d_{1} = 16; d_{2} = 14; T_{1} = 273 K, T_{2} = ?$

$d_{1} T_{1} = d_{2} T_{2}$

$16 \times 273 = 14 \times T_{2}$

$T_{2} = 312 K$

$T_{2} = 312 - 273 = 39 ℃$

Q. The density of O2​ is 16 at NTP. At what temperature(in oC) its density will be 14? Consider that the pressure remains constant.

As d=RTPM​ d1​T1​=d2​T2​ When p remains constant d1​=16;d2​=14;T1​=273K,T2​=? d1​T1​=d2​T2​ 16×273=14×T2​ T2​=312K T2​=312−273=39℃

Q. The density of $O_{2}$ is 16 at NTP. At what temperature(in ^oC) its density will be 14? Consider that the pressure remains constant.

As $d = \frac{P M}{R T}$

$d_{1} T_{1} = d_{2} T_{2}$

When $p$ remains constant

$d_{1} = 16; d_{2} = 14; T_{1} = 273 K, T_{2} = ?$

$d_{1} T_{1} = d_{2} T_{2}$

$16 \times 273 = 14 \times T_{2}$

$T_{2} = 312 K$

$T_{2} = 312 - 273 = 39 ℃$