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Q. The density of $O_{2}$ is 16 at NTP. At what temperature(in oC) its density will be 14? Consider that the pressure remains constant.

NTA AbhyasNTA Abhyas 2020States of Matter

Solution:

As $\text{d}=\frac{\text{P} \text{M}}{\text{R} \text{T}}$

$\text{d}_{1}\text{T}_{1}=\text{d}_{2}\text{T}_{2}$

When $\text{p}$ remains constant

$\text{d}_{1}=16;\text{d}_{2}=14;\text{T}_{1}=273 \, \text{K}, \, \text{T}_{2}=?$

$\text{d}_{1}\text{T}_{1}=\text{d}_{2}\text{T}_{2}$

$16\times 273=14\times \text{T}_{2}$

$\text{T}_{2}=312 \, \text{K}$

$\text{T}_{2}=312-273=39\text{℃}$