The density of Cu is 8.94 g cm -3. The quantity of electricity needed to plate an area 10 cm × 10 cm to a thickness of 10-2 cm using CuSO 4 solution would be

Question

The density of Cu is 8.94 g cm -3. The quantity of electricity needed to plate an area 10 cm × 10 cm to a thickness of 10-2 cm using CuSO 4 solution would be (A) 13586 C (B) 27172 C (C) 40758 C (D) 20348 C

Tardigrade Admin · Accepted Answer

Volume: 10 × 10 × 10-2=1 cm 3 mass of Cu =8.94 g mole of Cu =(8.94/63.5) EQuivalent of Cu =(8.94/63.5) × 2 Charge =(8.94/63.5) × 2 × 96500 C =27172 C

Q. The density of $C u$ is $8.94 g c m^{- 3}$ . The quantity of electricity needed to plate an area $10 c m \times 10 c m$ to a thickness of $1 0^{- 2} c m$ using $C u S O_{4}$ solution would be

13586 C

27172 C

40758 C

20348 C

Volume : $10 \times 10 \times 1 0^{- 2} = 1 c m^{3}$
mass of $C u = 8.94 g$
mole of $C u = \frac{8.94}{63.5}$
EQuivalent of $C u = \frac{8.94}{63.5} \times 2$
Charge $= \frac{8.94}{63.5} \times 2 \times 96500 C = 27172 C$

Q. The density of Cu is 8.94gcm−3. The quantity of electricity needed to plate an area 10cm×10cm to a thickness of 10−2cm using CuSO4​ solution would be