The density of a monobasic strong acid (Molar mass 24.2 g mol) is 1.21 kg L. The volume of its solution required for the complete neutralization of 25 mL of 0.24 M NaOH is × 10-2 mL (Nearest integer)

Question

The density of a monobasic strong acid (Molar mass 24.2 g mol) is 1.21 kg L. The volume of its solution required for the complete neutralization of 25 mL of 0.24 M NaOH is × 10-2 mL (Nearest integer) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

millimole of NaOH =0.24 × 25 ∴ millimole of acid =0.24 × 25 ⇒ mass of acid =0.24 × 25 × 24.2 mg for pure acid, V =( w / d ) ;( d =1.21 kg / L =1.21 g / ml ) ∴ V = (0.24 × 25 × 24.2/1.12) × 10-3 =120 × 10-3 ml =12 × 10-2 ml

Q. The density of a monobasic strong acid (Molar mass 24.2g mol) is 1.21kgL. The volume of its solution required for the complete neutralization of 25mL of 0.24MNaOH is ___×10−2mL (Nearest integer)

millimole of NaOH=0.24×25 ∴ millimole of acid =0.24×25 ⇒ mass of acid =0.24×25×24.2mg for pure acid, V=dw​;(d=1.21kg/L=1.21g/ml) ∴V=1.120.24×25×24.2​×10−3 =120×10−3ml =12×10−2ml

Q. The density of a monobasic strong acid (Molar mass $24.2 g$ mol) is $1.21 k g L$ . The volume of its solution required for the complete neutralization of $25 m L$ of $0.24 M N a O H$ is ___ $\times 1 0^{- 2} m L$ (Nearest integer)