The density of a gas is 1.964 g dm -3 at 273 k and 76 cm Hg. The gas is

Question

The density of a gas is 1.964 g dm -3 at 273 k and 76 cm Hg. The gas is (A) CH4 (B) C2H6 (C) CO2 (D) Xe

Tardigrade Admin · Accepted Answer

We know that P V=n R T or P V =(w/m) R T or m =(w/V) (R T/P) or M=d (R T/P) d =1.964 g / dm 3=1.964 × 10-3 g / cc P =76 cm =1 atm R =0.0812 L atm K -1 mol -1 =82.1 cc atm K -1 mol -1 T =273 K m =(1.964 × 10-3 × 82.1 × 273/1)=44 The molecular weight of CO 2 is 44 . So, the gas is CO 2

Q. The density of a gas is $1.964 g d m^{- 3}$ at $273 k$ and $76 c m H g$ . The gas is

$C H_{4}$

$C_{2} H_{6}$

$C O_{2}$

$X e$

Q. The density of a gas is 1.964gdm−3 at 273k and 76cmHg. The gas is

CH4​

C2​H6​

CO2​

Xe

We know that PV=nRT or PV=mw​RT or m=Vw​PRT​ or M=dPRT​ d=1.964g/dm3=1.964×10−3g/cc P=76cm=1atm R=0.0812LatmK−1mol−1 =82.1ccatmK−1mol−1 T=273K m=11.964×10−3×82.1×273​=44 The molecular weight of CO2​ is 44 . So, the gas is CO2​

Q. The density of a gas is $1.964 g d m^{- 3}$ at $273 k$ and $76 c m H g$ . The gas is

$C H_{4}$

$C_{2} H_{6}$

$C O_{2}$

$X e$