The density of a circular disc is given as σ = ρ0x where 'x' is the distance from the centre. Its moment of inertia about an axis perpendicular to its plane and passing through its edge is :

Question

The density of a circular disc is given as σ = ρ0x where 'x' is the distance from the centre. Its moment of inertia about an axis perpendicular to its plane and passing through its edge is : (A) (15/16) ρ0 π R5  (B) (16/15) ρ0 π R5  (C) (6/5) ρ0 π R5  (D) (5/6) ρ0 π R5

Tardigrade Admin · Accepted Answer

Correct answer is (b) (16/15) ρ0 π R5

Q. The density of a circular disc is given as $σ = ρ_{0} x$ where 'x' is the distance from the centre. Its moment of inertia about an axis perpendicular to its plane and passing through its edge is :

$\frac{15}{16} ρ_{0} π R^{5}$

$\frac{16}{15} ρ_{0} π R^{5}$

$\frac{6}{5} ρ_{0} π R^{5}$

$\frac{5}{6} ρ_{0} π R^{5}$

Correct answer is (b) $\frac{16}{15} ρ_{0} π R^{5}$

Q. The density of a circular disc is given as σ=ρ0​x where 'x' is the distance from the centre. Its moment of inertia about an axis perpendicular to its plane and passing through its edge is :

1615​ρ0​πR5

1516​ρ0​πR5

56​ρ0​πR5

65​ρ0​πR5