The density of 3M solution of sodium chloride is 1.252 g mL-1. The molality of the solution will be: (molar mass, NaCl = 585 g mol-1)

Question

The density of 3M solution of sodium chloride is 1.252 g mL-1. The molality of the solution will be: (molar mass, NaCl = 585 g mol-1) (A) 260 m (B) 2.18 m (C) 2.79 m (D) 3.00 m

Tardigrade Admin · Accepted Answer

The relation between molarity (M) and molality (m) is d=M((1/m)+(M2/1000)), M2= Mol. mass of solute On putting value 1.252=3((1/m)+(58.5/1000)) on solving m = 2.79

Q. The density of $3 M$ solution of sodium chloride is $1.252 g m L^{- 1}$ . The molality of the solution will be:
(molar mass, $N a Cl = 585 g m o l^{- 1}$ )

260 m

2.18 m

2.79 m

3.00 m

The relation between molarity (M) and molality (m) is
$d = M (\frac{1}{m} + \frac{M _{2}}{1000}), M_{2} =$ Mol. mass of solute
On putting value
$1.252 = 3 (\frac{1}{m} + \frac{58.5}{1000})$
on solving $m = 2.79$

Q. The density of 3M solution of sodium chloride is 1.252gmL−1. The molality of the solution will be: (molar mass, NaCl=585gmol−1)