The density of 3 M solution of NaCl is 1.0 g mL -1. Molality of the solution is × 10-2 m. (Nearest integer). Given: Molar mass of Na and Cl is 23 and 35.5 g mol -1 respectively.

Question

The density of 3 M solution of NaCl is 1.0 g mL -1. Molality of the solution is × 10-2 m. (Nearest integer). Given: Molar mass of Na and Cl is 23 and 35.5 g mol -1 respectively. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

m =(1000 × M /1000 × d - M × M . W text of solute ) =(1000 × 3/1000 × 1-(3 × 58.5))=3.64 =364 × 10-2

Q. The density of $3 M$ solution of $N a Cl$ is $1.0 g m L^{- 1}$ . Molality of the solution is _______ $\times 1 0^{- 2} m$ . (Nearest integer).
Given: Molar mass of $N a$ and $Cl$ is $23$ and $35.5 g m o l^{- 1}$ respectively.

$m = \frac{1000 \times M}{1000 \times d - M \times M . W of solute}$
$= \frac{1000 \times 3}{1000 \times 1 - ( 3 \times 58.5 )} = 3.64$
$= 364 \times 1 0^{- 2}$

Q. The density of 3M solution of NaCl is 1.0gmL−1. Molality of the solution is _______ ×10−2m. (Nearest integer). Given: Molar mass of Na and Cl is 23 and 35.5gmol−1 respectively.

m=1000×d−M×M.W of solute 1000×M​ =1000×1−(3×58.5)1000×3​=3.64 =364×10−2

Q. The density of $3 M$ solution of $N a Cl$ is $1.0 g m L^{- 1}$ . Molality of the solution is _______ $\times 1 0^{- 2} m$ . (Nearest integer).
Given: Molar mass of $N a$ and $Cl$ is $23$ and $35.5 g m o l^{- 1}$ respectively.

$m = \frac{1000 \times M}{1000 \times d - M \times M . W of solute}$
$= \frac{1000 \times 3}{1000 \times 1 - ( 3 \times 58.5 )} = 3.64$
$= 364 \times 1 0^{- 2}$