Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The degree of the differential equation y(x)=1 +(dy/dx)+(1/1.2)((dy/dx))2+(1/1.2.3)((dy/dx))3+......... is
Q. The degree of the differential equation
y
(
x
)
=
1
+
d
x
d
y
+
1.2
1
(
d
x
d
y
)
2
+
1.2.3
1
(
d
x
d
y
)
3
+
.........
is
5073
220
BITSAT
BITSAT 2005
Report Error
A
2
0%
B
3
20%
C
1
60%
D
none of these
20%
Solution:
Given that
y
(
x
)
=
1
+
d
x
d
y
=
1.2
1
(
d
x
d
y
)
2
+
1.2.3
1
(
d
x
d
y
)
3
+
……
or
y
(
x
)
=
1
+
1
!
1
(
d
x
d
y
)
+
2
!
1
(
d
x
d
y
)
2
+
3
!
1
(
d
x
d
y
)
3
+
……
y
(
x
)
=
e
d
y
/
d
x
Taking log on both sides, we get
lo
g
y
(
x
)
=
d
x
d
y
∴
The degree of this equation is
1
.