Question

The degree of the differential equation $y_2^{3/2}-y_1^{1/2}-4=0$ is

• A. 6
• B. 3
• C. 2
• D. 4

Answer 1

Answer: (A)

Given, $y_2^{3/2}=y_1^{1/2}+4$ Squaring on both sides, we get $y_2^3=y_1+16+8y_1^{1/2}$ $\Rightarrow$ ${(y_2^3-y_1-16)}^2=64y_1$ $\Rightarrow$ $y_2^6-32y_2^3-2y_2^3.y_1+y_1^2-32y_1+256=0$ Hence, the degree of the given equation is 6.