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Question
Mathematics
The degree of the differential equation [1+((dy/dx))2]5/3 =(d2y/dx2) is
Q. The degree of the differential equation
[
1
+
(
d
x
d
y
)
2
]
5/3
=
d
x
2
d
2
y
is
3102
224
WBJEE
WBJEE 2008
Differential Equations
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A
1
9%
B
5
25%
C
3
10
34%
D
3
31%
Solution:
The given differential equation is
[
1
+
(
d
x
d
y
)
2
]
5/3
=
d
x
2
d
2
y
⇒
(
d
x
d
2
y
)
3
=
[
1
+
(
d
x
d
y
)
2
]
5
From above it is clear that the degree of the given differential equation is
3
.