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Mathematics
The degree of the differential equation [1+((dy/dx))2]5/3 =(d2y/dx2) is
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Q. The degree of the differential equation
$\left[1+\left(\frac{dy}{dx}\right)^{2}\right]^{5/3} =\frac{d^{2}y}{dx^{2}} $ is
WBJEE
WBJEE 2008
Differential Equations
A
$1$
9%
B
$5$
25%
C
$\frac{10}{3}$
34%
D
$3$
31%
Solution:
The given differential equation is
$\left[1+\left(\frac{dy}{dx}\right)^{2}\right]^{5/3} =\frac{d^{2}y}{dx^{2}} $
$\Rightarrow \left(\frac{d^{2}y}{dx}\right)^{3} = \left[1+\left(\frac{dy}{dx}\right)^{2}\right]^{5}$
From above it is clear that the degree of the given differential equation is $3$.