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Question
Mathematics
The degree of the differential equation[1+((dy/dx))2]3/2=l(d2y/dx2) is
Q. The degree of the differential equation
[
1
+
(
d
x
d
y
)
2
]
3/2
=
l
d
x
2
d
2
y
is
2664
236
Differential Equations
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A
1
18%
B
2
48%
C
3
27%
D
4
7%
Solution:
(
1
+
(
d
x
d
y
)
2
)
3/2
=
d
x
2
d
2
y
⇒
(
1
+
(
d
x
d
y
)
2
)
3
=
(
d
x
2
d
2
y
)
2
Its degree is
2
.