The degree of ionization of 0.10 M lactic acid is 4.0 % The value of Kc is

Question

The degree of ionization of 0.10 M lactic acid is 4.0 % <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/01ec1c1f08fd7e6a05a5155ea6737ae4-.png" /> The value of Kc is (A) 1.66 × 10-5 (B) 1.66 × 10-4 (C) 1.66 × 10-3 (D) 1.66 × 10-2

Tardigrade Admin · Accepted Answer

% dissociation =4 % degree of dissociation (α)=(4/100)=0.04 For lactic acid <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/1a0570edbbd47c8baeda322f2414bccf-.png" /> ∴ Kc =(C α ⋅ C α/C(1-α)) =(C α2/(1-α)) =(0.1 × 0.04 × 0.04/(1-0.04)) =(1.6 × 10-4/0.96)=1.66 × 10-4

Q. The degree of ionization of $0.10 M$ lactic acid is $4.0%$

The value of $K_{c}$ is

$1.66 \times 1 0^{- 5}$

$1.66 \times 1 0^{- 4}$

$1.66 \times 1 0^{- 3}$

$1.66 \times 1 0^{- 2}$

$%$ dissociation $= 4%$

degree of dissociation $(α) = \frac{4}{100} = 0.04$

For lactic acid

$∴ K_{c} = \frac{C α \cdot C α}{C ( 1 - α )} = \frac{C α ^{2}}{( 1 - α )}$

$= \frac{0.1 \times 0.04 \times 0.04}{( 1 - 0.04 )}$

$= \frac{1.6 \times 1 0 ^{- 4}}{0.96} = 1.66 \times 1 0^{- 4}$

Q. The degree of ionization of 0.10M lactic acid is 4.0% The value of Kc​ is

1.66×10−5

1.66×10−4

1.66×10−3

1.66×10−2