Question

The degree of ionisation of an acid $HA$ is $0.00001$ at $0.1M$ concentration. Its dissociation constant will be

• A. $10^{-9}$
• B. $10^{-11}$
• C. $10^{-8}$
• D. $10^{-7}$

Answer 1

Answer: (B)

$K_a=c{\alpha }^2$
$=0.1\times {\left(10^{-5}\right)}^2$
$=10^{-11}$