The degree of dissociation of an electrolyte is α and its van't Hoff factor is i . The number of ions obtained by complete dissociation of 1 molecule of the electrolyte is:

Question

The degree of dissociation of an electrolyte is α and its van't Hoff factor is i . The number of ions obtained by complete dissociation of 1 molecule of the electrolyte is: (A) (i + α - 1/α ) (B) i-α -1 (C) (i - 1/α ) (D) (i + 1 + α /1 - α )

Tardigrade Admin · Accepted Answer

i=1+(n - 1)α so n=(i + α - 1/α )

Q. The degree of dissociation of an electrolyte is $α$ and its van't Hoff factor is $i$ . The number of ions obtained by complete dissociation of $1$ molecule of the electrolyte is:

$\frac{i + α - 1}{α}$

$i - α - 1$

$\frac{i - 1}{α}$

$\frac{i + 1 + α}{1 - α}$

$i = 1 + (n - 1) α$ so $n = \frac{i + α - 1}{α}$

Q. The degree of dissociation of an electrolyte is α and its van't Hoff factor is i . The number of ions obtained by complete dissociation of 1 molecule of the electrolyte is:

αi+α−1​

i−α−1

αi−1​

1−αi+1+α​