Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The degree of differential equation (d2 y/d x2)+((d y/d x))3+6 y=0 is:
Q. The degree of differential equation
d
x
2
d
2
y
+
(
d
x
d
y
)
3
+
6
y
=
0
is:
1197
194
Jharkhand CECE
Jharkhand CECE 2002
Report Error
A
1
B
3
C
2
D
5
Solution:
The power of highest derivative is called a degree.
Given differential equation is
d
x
2
d
2
y
+
(
d
x
d
y
)
3
+
6
y
=
0
Here, degree is
1
.
If the given differential equation is in the form of radicals, then first we convert the radicals into integers.