Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The degree of (3 x3+10 x2+x-14/3 x2+13 x+14) is
Q. The degree of
3
x
2
+
13
x
+
14
3
x
3
+
10
x
2
+
x
−
14
is____
90
129
Polynomials
Report Error
Answer:
1
Solution:
3
x
2
+
13
x
+
14
3
x
3
+
10
x
2
+
x
−
14
=
(
7
x
+
7
)
(
x
+
2
)
(
3
x
+
7
)
(
x
+
2
)
(
x
−
1
)
=
x
−
1
∴
The degree is
1.