The degeneracy of hydrogen atom that has energy equal to -(R H /9) (where R H is Rydberg constant) is

Question

The degeneracy of hydrogen atom that has energy equal to -(R H /9) (where R H is Rydberg constant) is (A) 4 (B) 6 (C) 9 (D) 12

Tardigrade Admin · Accepted Answer

-(R H /n2)=-(R H /9) ⇒ n=3 <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/9d2869a50aa8041b90452815cd7c9384-.png" /> Degeneracy = 1 + 3 + 5 = 9

Q. The degeneracy of hydrogen atom that has energy equal to $- \frac{R _{H}}{9}$ (where $R_{H}$ is Rydberg constant) is

4

6

9

12

$- \frac{R _{H}}{n ^{2}} = - \frac{R _{H}}{9} \Rightarrow n = 3$

Degeneracy $= 1 + 3 + 5 = 9$

Q. The degeneracy of hydrogen atom that has energy equal to −9RH​​ (where RH​ is Rydberg constant) is

4

6

9

12

−n2RH​​=−9RH​​⇒n=3 Degeneracy =1+3+5=9

Q. The degeneracy of hydrogen atom that has energy equal to $- \frac{R _{H}}{9}$ (where $R_{H}$ is Rydberg constant) is

$- \frac{R _{H}}{n ^{2}} = - \frac{R _{H}}{9} \Rightarrow n = 3$

Degeneracy $= 1 + 3 + 5 = 9$