The degeneracy of hydrogen atom that has energy equal to (-R H /9) is (where R H = Rydberg constant)

Question

The degeneracy of hydrogen atom that has energy equal to (-R H /9) is (where R H = Rydberg constant) (A) 6 (B) 8 (C) 5 (D) 9

Tardigrade Admin · Accepted Answer

Here, (-R H /n2)=(-R H /9) ⇒ n=3 <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/7ff3b671acaac1eeba6064cbccca591d-.png" />

Q. The degeneracy of hydrogen atom that has energy equal to $\frac{- R _{H}}{9}$ is (where $R_{H} =$ Rydberg constant)

6

8

5

9

Here, $\frac{- R _{H}}{n ^{2}} = \frac{- R _{H}}{9}$
$\Rightarrow n = 3$

Q. The degeneracy of hydrogen atom that has energy equal to 9−RH​​ is (where RH​= Rydberg constant)

6

8

5

9

Here, n2−RH​​=9−RH​​ ⇒n=3

Q. The degeneracy of hydrogen atom that has energy equal to $\frac{- R _{H}}{9}$ is (where $R_{H} =$ Rydberg constant)

Here, $\frac{- R _{H}}{n ^{2}} = \frac{- R _{H}}{9}$
$\Rightarrow n = 3$