The decreasing order of oxidation number of Mn in the given compounds is I. K 2 MnO 4 II. Mn 2 O 5 III. MnO 4- IV. MnCl 2

Question

The decreasing order of oxidation number of Mn in the given compounds is I. K 2 MnO 4 II. Mn 2 O 5 III. MnO 4- IV. MnCl 2 (A) IV > II > III > I (B) IV > III > II > I (C) III > I > II > IV (D) IV > II > I > III

Tardigrade Admin · Accepted Answer

For the given compounds, <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/5760c90b923c3bfe63e1dfa9ec059958-.png" /> Decreasing order of oxidation number is III > I > II > IV

Q. The decreasing order of oxidation number of $M n$ in the given compounds is
I. $K_{2} M n O_{4}$
II. $M n_{2} O_{5}$
III. $M n O_{4}^{-}$
IV. $M n C l_{2}$

$I V > II > III > I$

$I V > III > II > I$

$III > I > II > I V$

$I V > II > I > III$

For the given compounds,

Decreasing order of oxidation number is
$III > I > II > I V$

Q. The decreasing order of oxidation number of Mn in the given compounds is I. K2​MnO4​ II. Mn2​O5​ III. MnO4−​ IV. MnCl2​

IV>II>III>I

IV>III>II>I

III>I>II>IV

IV>II>I>III