The decreasing order of bond angles in BF3 , NH3 , PF3 and I3- is

Question

The decreasing order of bond angles in BF3 , NH3 , PF3 and I3- is (A) I3- > NH3 > PF3 > BF3 (B) I3- > BF3 > NH3 > PF3 (C) BF3 > I3- > PF3 > NH3 (D) BF3 > NH3 > PF3 > I3-

Tardigrade Admin · Accepted Answer

The shape of the given molecules is as follows: BF3: Planar triangle with bond angles of 120°.

NH 3: Trigonal pyramidal with bond angles of 107° .

I 3-: Linear with bond angles 180°.

PF 3: Trigonal pyramidal with bond angles of 97.8° .

Q. The decreasing order of bond angles in $B F_{3}, N H_{3}, P F_{3}$ and $I_{3}^{-}$ is

$I_{3}^{-} > N H_{3} > P F_{3} > B F_{3}$

$I_{3}^{-} > B F_{3} > N H_{3} > P F_{3}$

$B F_{3} > I_{3}^{-} > P F_{3} > N H_{3}$

$B F_{3} > N H_{3} > P F_{3} > I_{3}^{-}$

Q. The decreasing order of bond angles in BF3​,NH3​,PF3​ and I3​− is

I3​−>NH3​>PF3​>BF3​

I3​−>BF3​>NH3​>PF3​

BF3​>I3​−>PF3​>NH3​

BF3​>NH3​>PF3​>I3​−

The shape of the given molecules is as follows: BF3​ : Planar triangle with bond angles of 120∘. NH3​ : Trigonal pyramidal with bond angles of 107∘. I3−​ : Linear with bond angles 180∘. PF3​ : Trigonal pyramidal with bond angles of 97.8∘.

Q. The decreasing order of bond angles in $B F_{3}, N H_{3}, P F_{3}$ and $I_{3}^{-}$ is

$I_{3}^{-} > N H_{3} > P F_{3} > B F_{3}$

$I_{3}^{-} > B F_{3} > N H_{3} > P F_{3}$

$B F_{3} > I_{3}^{-} > P F_{3} > N H_{3}$

$B F_{3} > N H_{3} > P F_{3} > I_{3}^{-}$