The decomposition of a certain mass of CaCO3 gave 11.2 dm3 of CO2 gas at STP. The mass of KOH required to completely neutralize the gas is

Question

The decomposition of a certain mass of CaCO3 gave 11.2 dm3 of CO2 gas at STP. The mass of KOH required to completely neutralize the gas is (A) 56 g (B) 28 g (C) 42 g (D) 20 g

Tardigrade Admin · Accepted Answer

Weight of 11.2 dm3 of CO2 gas at STP =44/2=22 g underset56 g KOH + underset44 gCO 2 longrightarrow KHCO 3 ∴ KOH required for complete neutralization of CO2(44 g)=56 g ∴ KOH required for neutralization of 22 g of CO2=(56/44)× 22=28 g

Q. The decomposition of a certain mass of $C a C O_{3}$ gave $11.2 d m^{3}$ of $C O_{2}$ gas at STP. The mass of $K O H$ required to completely neutralize the gas is

56 g

28 g

42 g

20 g

Weight of $11.2 d m^{3}$ of $C O_{2}$ gas at STP
$= 44/2 = 22 g$
$56 g K O H + 44 g C O_{2} ⟶ KH C O_{3}$
$∴ K O H$ required for complete neutralization of $C O_{2} (44 g) = 56 g$
$∴ K O H$ required for neutralization of $22 g$ of $C O_{2} = \frac{56}{44} \times 22 = 28 g$

Q. The decomposition of a certain mass of CaCO3​ gave 11.2dm3 of CO2​ gas at STP. The mass of KOH required to completely neutralize the gas is