The de Broglie wavelength of an electron (mass = 1 × 10-30 kg, charge = 1.6 × 10 -19 C) with a kinetic energy of 200 eV is (Planck’s constant = 6.6 × 10-34 J s)

Question

The de Broglie wavelength of an electron (mass = 1 × 10-30 kg, charge = 1.6 × 10 -19 C) with a kinetic energy of 200 eV is (Planck’s constant = 6.6 × 10-34 J s) (A) 9.60 × 10-11 m (B) 8.25 × 10-11 m (C) 6.25 × 10-11 m (D) 5.00 × 10-11 m

Tardigrade Admin · Accepted Answer

The de-Broglie wavelength, λ=(h/√2 m k) Given, h =6.6 × 10-34 J - s m =1 × 10-30 kg K=200 eV =200 × 1.6 × 10-19 J Substituting all these values λ =(6.6 × 10-34/√2 × 1 × 10-30 × 200 × 1.6 × 10-19) =0.825 × 10-10=8.25 × 10-11 m

Q. The de Broglie wavelength of an electron (mass $= 1 \times 1 0^{- 30}$ kg, charge = $1.6 \times 1 0^{- 19}$ C) with a kinetic energy of $200 e V$ is (Planck’s constant = $6.6 \times 1 0^{- 34}$ J s)

$9.60 \times 1 0^{- 11} m$

$8.25 \times 1 0^{- 11} m$

$6.25 \times 1 0^{- 11} m$

$5.00 \times 1 0^{- 11} m$

Q. The de Broglie wavelength of an electron (mass =1×10−30 kg, charge = 1.6×10−19 C) with a kinetic energy of 200eV is (Planck’s constant = 6.6×10−34 J s)

9.60×10−11m

8.25×10−11m

6.25×10−11m

5.00×10−11m

The de-Broglie wavelength, λ=2mk​h​ Given, h=6.6×10−34J−s m=1×10−30kg K=200eV=200×1.6×10−19J Substituting all these values λ=2×1×10−30×200×1.6×10−19​6.6×10−34​ =0.825×10−10=8.25×10−11m

Q. The de Broglie wavelength of an electron (mass $= 1 \times 1 0^{- 30}$ kg, charge = $1.6 \times 1 0^{- 19}$ C) with a kinetic energy of $200 e V$ is (Planck’s constant = $6.6 \times 1 0^{- 34}$ J s)

$9.60 \times 1 0^{- 11} m$

$8.25 \times 1 0^{- 11} m$

$6.25 \times 1 0^{- 11} m$

$5.00 \times 1 0^{- 11} m$