The de Broglie wavelength of an electron and the wavelength of a photon are the same. The ratio between the energy of that photon and the momentum of that electron is ( c is velocity of light, h is Planck's constant)

Question

The de Broglie wavelength of an electron and the wavelength of a photon are the same. The ratio between the energy of that photon and the momentum of that electron is ( c is velocity of light, h is Planck's constant) (A) h (B) c (C) (1/h) (D) (1/c)

Tardigrade Admin · Accepted Answer

According to question, we have
De Broglie wavelength of electron

=

Wavelength of photon

\frac{h}{p _{e l ec t ro n}} = \frac{h c}{E _{p h o t o n}}

, where

p

is the momentum of electron,

c

is speed of light,

E

is energy of photon and

h

is Planck's constant.

\frac{E _{p h o t o n}}{p _{e l ec t ro n}} = \frac{h c}{h} = c

Q. The de Broglie wavelength of an electron and the wavelength of a photon are the same. The ratio between the energy of that photon and the momentum of that electron is ( $c$ is velocity of light, $h$ is Planck's constant)

$h$

$c$

$\frac{1}{h}$

$\frac{1}{c}$

Q. The de Broglie wavelength of an electron and the wavelength of a photon are the same. The ratio between the energy of that photon and the momentum of that electron is ( c is velocity of light, h is Planck's constant)

h

c

h1​

c1​

According to question, we have De Broglie wavelength of electron = Wavelength of photon pelectron​h​=Ephoton​hc​ , where p is the momentum of electron, c is speed of light, E is energy of photon and h is Planck's constant. pelectron​Ephoton​​=hhc​=c

Q. The de Broglie wavelength of an electron and the wavelength of a photon are the same. The ratio between the energy of that photon and the momentum of that electron is ( $c$ is velocity of light, $h$ is Planck's constant)

$h$

$c$

$\frac{1}{h}$

$\frac{1}{c}$