The de-Broglie wavelength of a particle of kinetic energy ' K ' is λ; the wavelength of the particle, if its kinetic energy is (K/4) is

Question

The de-Broglie wavelength of a particle of kinetic energy ' K ' is λ; the wavelength of the particle, if its kinetic energy is (K/4) is (A) (λ/2) (B) 4 λ (C) λ (D) 2 λ

Tardigrade Admin · Accepted Answer

λ propto (1/√ k ) (λ1/λ2)=√( k 2/ k 1),=√( k /4 k )=(1/2) λ2=2 λ

Q. The de-Broglie wavelength of a particle of kinetic energy ' $K$ ' is $λ$ ; the wavelength of the particle, if its kinetic energy is $\frac{K}{4}$ is

$\frac{λ}{2}$

$4 λ$

$λ$

$2 λ$

$λ \propto \frac{1}{k}$
$\frac{λ _{1}}{λ _{2}} = \frac{k _{2}}{k _{1}}, = \frac{k}{4 k} = \frac{1}{2}$
$λ_{2} = 2 λ$

Q. The de-Broglie wavelength of a particle of kinetic energy ' K ' is λ; the wavelength of the particle, if its kinetic energy is 4K​ is

2λ​

4λ

λ

2λ

λ∝k​1​ λ2​λ1​​=k1​k2​​​,=4kk​​=21​ λ2​=2λ

Q. The de-Broglie wavelength of a particle of kinetic energy ' $K$ ' is $λ$ ; the wavelength of the particle, if its kinetic energy is $\frac{K}{4}$ is

$\frac{λ}{2}$

$4 λ$

$λ$

$2 λ$

$λ \propto \frac{1}{k}$
$\frac{λ _{1}}{λ _{2}} = \frac{k _{2}}{k _{1}}, = \frac{k}{4 k} = \frac{1}{2}$
$λ_{2} = 2 λ$