The de-Broglie wavelength of a neutron in thermal equilibrium with heavy water at a temperature T (Kelvin) and mass m, is :

Question

The de-Broglie wavelength of a neutron in thermal equilibrium with heavy water at a temperature T (Kelvin) and mass m, is : (A) (h/√3m kT) (B) (2h/√3m kT) (C) (2h/√m kT) (D) (h/√m kT)

Tardigrade Admin · Accepted Answer

de-Broglie wavelength λ =(h/m v) =(h/√2 m( KE )) =(h/√2 m((3)2 k T)) λ =(h/√3 m k T)

Q. The de-Broglie wavelength of a neutron in thermal equilibrium with heavy water at a temperature $T$ (Kelvin) and mass $m$ , is :

$\frac{h}{3 mk T}$

$\frac{2 h}{3 mk T}$

$\frac{2 h}{mk T}$

$\frac{h}{mk T}$

de-Broglie wavelength
$λ = \frac{h}{m v}$
$= \frac{h}{2 m ( K E )}$
$= \frac{h}{2 m ( \frac{3}{2} k T )}$
$λ = \frac{h}{3 mk T}$

Q. The de-Broglie wavelength of a neutron in thermal equilibrium with heavy water at a temperature T (Kelvin) and mass m, is :

3mkT​h​

3mkT​2h​

mkT​2h​

mkT​h​